Chemistry, asked by solankivivek665, 9 months ago

The molar conductivities at infinite dilution of
potassium chloride, hydrochloric acid and potas-
sium acetate are 130-1, 379.4 and 95-60-'cm
mor respectively. Calculate the value of molar
conductivity at infinite dilution for acctic acid. If
the molar conductivity of a given acetic acid solu-
tion is 48-5 2-1 cmmorat 25°C, calculate the
degree of dissociation of acetic acid at this
temperature.​

Answers

Answered by kailashmeena123rm
19

\huge \:  \red   \star \: {  \large \pink {  \underline\mathcal{ANSWER}} }  \:  \red\star \: </p><p> \\  \\

 \\  \green{ \mathrm{concept}}  </p><p> \\    \\

  • kholrausch's law

  •  \\  \footnotesize{  \bold{\alpha = \frac{ \land_m }{ {  \land_m}^{ o}}  }} \\  \\

  •  \footnotesize{  \text{where} \: \:  \:   \alpha } \:  \:  \:  \text{is degree of dissociation. }

 \\  \\  \green{ \mathrm{solution}} \\  \\

 \\  {\land_m}^{ o}( \footnotesize{CH_3COOH}) =  \\  {\land_m}^{ o}(\footnotesize{CH_3COOK}) +  {\land_m}^{ o}(\footnotesize{HCl}) - {\land_m}^{ o}(\footnotesize{KCl}) \\  \\ {\land_m}^{ o}( \footnotesize{CH_3COOH}) =130.1 + 379.4 - 95.60 \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  = 413.90 \: \text{ unit }\: (  \text{same \: as \: given} ) \\  \\  \\

 \\  \\  \footnotesize{  \bold{\alpha = \frac{ \land_m }{ {  \land_m}^{ o}}  }}  =  \frac{48.5}{413.30}  = 0.113 \\  \\  \\

hope it helps

Similar questions
English, 4 months ago