Question

The molar conductivity of a 1.5 m solution of an electrolyte is 138.9 calculate conductivity of this solution

Answer 1

Explanation:

^m=(k×1000)÷m

^m=138.9 , m=1.5

138.9=(k×1000)÷1.5

138.9×1.5=k×1000

208.35÷1000=k

k=0.21(approx.)