The molar conductivity of CH3COOH at infinite dilution is found to be 387 ohm ^-1 cm^2 mol^-1 but at a dilution of 1 g mol in 1000 litres it is 55 ohm^-1 cm^2 mol^-1. What is percentage dissociation of the acid at a given dilution??
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Explanation:
mbhai9680
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Chemistry
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The molar conductivity of acetic acid at infinite dilution is 387 ohm-1 cm2 / mol. At the same temperature, but at a concentration of 1 mole in 1000 litres, it is 55 ohm-1 cm2 / mol. what is the percentage dissociation of acetic acid?
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Answer:
The percentage of dissociation of acetic acid is 14.2%
Explanation:
Given data:
molar conductivity of acetic acid at infinite dilution = 387 ohm^-1 cm^2 / mol.
=molar conductance of solution at particular or specific concentration
The temperature is maintained constant.
concentration of 1 mole in 1000 litres = 55 ohm^-1 cm^2 / mol
= Molar conduction at infinite dilution
To find:
the percentage dissociation of acetic acid
Solution:
We know that
Aplha = a = degree of dissociation
= molar conductance of solution at particular or specific concentration/
Molar conduction at infinite dilution
=55/387
= 0.142
Percentage of degree of dissociation= 0.142*100
=14.2%
Hence,
The percentage of dissociation of acetic acid is 14.2%
Note= The degree of dissociation cannot be greater than 1.