Question

the molar heat capacities at constant pressure ofH2(g) ,Cl2(g), hcl2(g)are respectively 29.3, 34.7,and 28.9jk-1. if the heat of formation of Hcl(g) at constant pressure at 293 k is -91.2 kj, what Will be it's heat of formation at 313k?​

Answer 1

Answer:

use the formula: (∆Q)heat energy = moles×Cp×∆T

10^3(kJ) = 100/18 (moles) × 75 × ∆T

by simplifying we get

∆T = 2.4 kelvin