Question

The molar mass of copper(II) chloride (CuCl2) is 134.45 g/mol. How many formula units of CuCl2 are present in 17.6 g of CuCl2?

7.88 × 1022 formula units

1.84 × 1023 formula units

1.91 × 1023 formula units

1.42 × 1024 formula units

Answer 1

Answer:

weight/mol.weight=N(CuCl2)/Avogadro's no

17.6/134.45×6.023×10²³=N(CuCl2)

N(CuCl2)=7.88×1022

Answer 2

There are $7.88\times 10^{22}$ formula units of $CuCl_2$

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{17.6g}{134.45g/mol}=0.130moles$

1 mole of $CuCl_2$ contains= $6.023\times 10^{23}$ formula units

0.130 moles of $CuCl_2$ contains= $\frac{6.023\times 10^{23}}{1}\times 0.130=0.78\times 10^{23}$ formula units

Thus there are $7.88\times 10^{22}$ formula units

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