Question

The molar mass of N2O as well as CO2 is 44g mol-1. At 250C and 1atm pressure, 2LN2O contains n molecules of gas. The number of CO2 molecules in 2L under same condition will be

Answer 1

Answer:

2n

Explanation:

PV=nRT

in this ques P, R, T are same,

so, $\frac{V1}{V2}$=$\frac{n1}{n2}$

n = ​$\frac{no.of molecules}{NA}$​ =number of moles

$\frac{1}{2}$​=$\frac{n}{molecules of CO2}$​​

the number of molecules of CO2​ =2n

Answer 2

Given:

• The molar mass of $N_2O$ and $CO_2$ = 44 g/mol
• Pressure = 1 atm
• Volume = 2 L

To Find:

• The number of molecules  $CO_2$ present in 2 L under the same condition.

Solution:

Consider the formula PV = nRT

Here the parameters P, R, and T are constant or the same, therefore the formula can be written as,

$V_1/V_2$ = $n_1/n_2$  and n = number of molecules/ Avogadro number

∴ The number of molecules of $CO_2$ is,

⇒ 1/2 = n/number molecules of $CO_2$

On cross-multiplying we get,

⇒ Number of molecules of $CO_2$ = 2n

∴ The number of molecules of $CO_2$ in 2 L under the same condition = 2n