Question

the molar solubility of CaF2 (Ksp = 5.3*10^-11 ) in 0.1 M BaF2 is

Answer 1

Answer:

The molar solubility of CaF2(Ksp = 5.3 * 10-11) in 0.1 M solution of NaF will be. (1) 5.3 * 10–10 mol L-1 (2) 5.3 * 10-11 mol L-1. (3) 5.3 * 10-8 mol L-1 (4) 5.3 x 10-9 mol L-1

Explanation:

explanation is in the answer itself

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Answer 2

Answer:

Explanation:

The molar solubility of CaF2(Ksp = 5.3 * 10-11) in 0.1 M solution of NaF will be. [NEET-2019 (Odisha)] (1) 5.3 * 10–10 mol L-1 (2) 5.3 * 10-11 mol L-1.

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