The molarity of 2 litre sodium hydroxide solution containing 8g of solute is
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volume of solution 2l
moles of solute o.5
therefore M =0.1
moles of solute o.5
therefore M =0.1
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NaOH=40g per mole
molarity= no of moles per litre of solution
M= (8)/(40*2)
molarity= no of moles per litre of solution
M= (8)/(40*2)
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