Question

The molarity of a solution obtained by mixing 750 ml of 0.5 M HCI with
250 ml of 2 M HCI will be​

Answer 1

Answer:

c=0,5/0,75

=0,67mol.dm

c=2/0,25

=8mol.dm

Answer 2

Explanation:

We know that,

$\sf M_1V_1+M_2V_2=M_fV_f$

• $\sf M_1=0.5 \: M$
• $\sf V_1=750 \: ml$
• $\sf M_2 =2 \: M$
• $\sf V_2 = 250 \:ml$
• $\sf V_f=750+250=1000\:ml$

$\sf M_f=\dfrac{M_1V_1+M_2V_2}{V_f}$

$\sf M_f=\dfrac{375+500}{1000}$

$\sf M_f=\dfrac{875}{1000}$

$\sf M_f=0.875\:M$