Question

The molarity of a solution obtained by mixing 750 ml of 5 0.5 m HCL with 250 ml of 2m HCL will be?

Answer 1

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From the formula ,Mf = M1V1 + M2V2/v1 + v2

Given ,
V1 = 750ml
M1= 0.5 M

V2 = 250ml
,M2 = 2M

=
$\frac{750 + \times 0.5 + 250 \times 2}{750 + 250} \\ = \frac{875}{1000} \\ = 0.875$

Answer = 0.875 M

Answer 2

$\underline{\underline{\Huge\mathfrak{Solution ;}}}$

Given ;-
• V1 = 750 ml.
• M1 = 0.5 m.

Using the Formula ;-

$= > mf = m1v1 + \frac{m2v2}{v1} + v2$

Let's Solve it ;-

$= > \frac{750 + 0.5 + 250 \times 2}{750 + 250} = \frac{875}{1000}$

$= > 0.875$

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