Question

The molarity of chloride ion (Cl-) when 200 ml of
3 (M) KCI is added to 300 ml of 2(M) MgCl, is__
(A)3.6 (M)
(B) 1.8 (M)
(C) 2.4 (M)
(D) 1.2 (M)​

Answer 1

Answer:

initial mole= final mole

(MV)kcl+(MV)Mgcl = M(V1+V2)

3×200 + 2×300. = M(300+200)

M = 1200/500

= 2.4 M

(c)