Chemistry, asked by abhaygami, 1 year ago

The molarity of CI in an aqueous solution which was (W/V) 2% NaCl, 4% CaCl2 and 6% NH4Cl will be
(A) 0.342
B) 0.721
(C) 1.12
(D) 2.18​

Answers

Answered by ashrafulislam01760
26

Answer:(D) 2.18​

Explanation:

w/v percentage means weight of solute in gm in 100ml of solute

2%NaCl has mole of Cl- =2/58.5

similarly 4% CaCl2will have 2*4/111

6% NH4Cl =6/53.5

total mole in 100 ml=2/58.5 +4/111 +6/53.5

in 1 lt of the solution=2.18 mole

molarity=2.18

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