Question

the molarity of sulphuric acid solution is .6 mol/kg.the total weight of the solution which contains 1kg of solvent?

Answer 1

There’s a mistake in question,
It should be “The Molality of sulphuric acid……”

Molality = Moles of solute / Mass of Solvent
0.6 = Moles of solute / (1 kg)
Moles of solute = 0.6 mol

Mass of solute = Moles of solute × Molar mass of solute
= 0.6 × 98 ……[∵ Molar mass of H₂SO₄ is 98 g/mol]
= 58.8 g

Mass of solution = Mass of solute + Mass of solvent
= 58.8g + 1000g
= 1058.8 g

Total weight of the solution is 1058.8 grams

Answer 2

Answer:

0.6 molarity means 0.6 moles in 1 kg

Mass of solute = molar mass × mass of solute

= 98×0.6

= 58.8g

1kg =1000g

1000g + 58.8 g =1058.8