Question

The molarity of the KOH solution which is 2.8% (mass/volume) solutions is –

(Atomic masses are :K = 39, O = 16, H = 1)

(A) 0.1 M (B) 0.5 M

(C) 0.2 M (D) 1 M​

Answer 1

Answer:

M(KOH) = 56g/ml

w = (mKOH/mSolution)x100% = 2.8%

c=?

c=n/V

n=m/M

assume that density of solution is approximately equal to density of water, therefore,ρ = 1g/ml

Suppose that, mSolution = 100g, therefore,

mKOH = w x mSolution/100% = 2.8x100/100% = 2.8g

mKOH = 2.8/56 = 0.05 mol

c = 0.05mol/0.1L = 0.5mol/L = M/5

Explanation:

B) 0.5M

Answer 2

Answer:

answer will be d am iright