Question

The molarity of the mixture is 100 ml of 0.1 M HCL and 0.2M 400ml of HCL

Answer 1

Explanation:

No.of milli moles HCl in 100 ml. 0.2 M HCl =0.2 x100 =20

No.of Mill moles of HCl in 200 ml.of 0.3 M HCl =0.3 x 200 =60

So no.of mili moles of HCl in the Total 300 ml.of HCl = 80

1000 ml.of the HCl will contain

=80 x1000/300 =266.7 milli moles

or the concentration of HCl in the resulting mixture is =0.2667 M or 0.2667 N

So pH = - log(0.2667) = 0.5740