Question

The mole fraction of solute in 10% (w/W) aqueous NaOH solution is​

Answer 1

Answer:

The morality is 2.78, must take into account the actual weight of 10 g of NaOH in 100 ml.

M=mol/L NaOH density is 2.13 g/mL

10g Naoh/40(g/mol)=0.25 mol

10% in 100 ml means 10 ml of NaOH and 90 ml of dilutent (water)

2.13*10 (%ofNaOH)= 21.3 is the weight of NaOH

For water grams are equal to mL so 90g water = 90 mL of water

21.3+90=111.3 total weight 111.3g/100 mL= 1.113g/ml density of 10%

Which means 100g/1.113(g/ml)=89.9 ml or 0.0898 L

0.25 mol/0.0898 L=2.78

Explanation:

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