Question

The mole fraction of solvent in 0.1 molal aqueous solution is​

Answer 1

1 molal aqueous solution means that 1 mol/kg that is 1 mol of solute is present in the 1000 g of the water(here the aqueous means that solvent is water).

Molar mass of the water mass of the water = 18 g \ mol 1000g =55.55 mol

Moles of solvent+Moles of Solute

moles od solvent = 55.55+ 0.1 55.55 = 0.9982

THE MILE FRACTION OF SOLVENT IN 0.1 MOLAR AQUEOUS SOLUTION IS O. 9982.....

#ANONYMOUS....❤

Answer 2

Given:

0.1 molal aqueous solution has been provided.

To find:

Mole fraction of solvent.

Calculation:

0.1 molal solution means 0.1 moles of solute in 1 kg of solvent.

So, moles of solute = 0.1

So, moles of solvent

$\rm{= \dfrac{1000}{18} = 55.55 \: moles}$

Let mole fraction of solvent be $\chi$.

$\sf{ \chi = \dfrac{n_{solvent}}{n_{solvent} + n_{solute}} }$

$\sf{ = > \chi = \dfrac{55.55}{55.55+ 0.1} }$

$\sf{ = > \chi = \dfrac{55.55}{55.65} }$

$\sf{ = > \chi = 0.998 }$

So, final answer is:

$\boxed{ \red{ \large{ \rm{ \chi = 0.998 }}}}$