Question

The mole of AgCl formed, when 17 g of AgNO is mixed with 1.435 g of NaCl is (Molar mass: AgNO 170g, AgCL 143.5 g)​

Answer 1

Answer:

AgNO + NaCl -> AgCl + NaNO

So ratio of each reactant and product is 1:1:1:1.

Thus moles of AgNO = 17/170

= 0.1 mol

Thus moles of NaCl = 1.435/143.5

= 0.001 mol

Since NaCl is lesser amount thus it is Limiting Reagent so we can get only 0.01 mol of AgCl when all NaCl is used up.

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Answer 2

ratio of each reactant and product is 1:1:1:1.

Thus moles of AgNO = 17/170

= 0.1 mol

Thus moles of NaCl = 1.435/143.5

= 0.001 mol

Since NaCl is lesser amount thus it is Limiting Reagent so we can get only 0.01 mol of AgCl when all NaCl is used up.

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Explanation: