Question

The mole percent of urea in 0.5 m aqueous solution of urea is

Answer 1

Answer:

molality of aqueous solution of urea is 0.5m

it means, 0.5 mole of urea present in 1 kg of water (solvent).

mass of water = 1kg or 1000g

molar mass of water = 18g/mol

so, number of mole of water = 1000/18 = 55.5 mol

so, no of mole of solution = no of mole of urea + no of mole of water

= 0.5 mol + 55.5 mol

= 56 mol

mole- percent of urea = no of mole of urea in solution/(no of mole of solution ) × 100

= 0.5/56 × 100

= 50/56

≈ 0.89 %

hence, 0.89 % of urea present in 0.5m aqueous solution of urea.

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Answer 2

Answer:

molality of aqueous solution of urea is 0.5m

it means, 0.5 mole of urea present in 1 kg of water (solvent).

mass of water = 1kg or 1000g

molar mass of water = 18g/mol

so, number of mole of water = 1000/18 = 55.5 mol

so, no of mole of solution = no of mole of urea + no of mole of water

= 0.5 mol + 55.5 mol

= 56 mol

mole- percent of urea = no of mole of urea in solution/(no of mole of solution ) × 100

= 0.5/56 × 100

= 50/56

≈ 0.89 %

hence, 0.89 % of urea present in 0.5m aqueous solution of urea.

Hope it helps you

Pls mark brainliest

Have a great day