Question

The sides of the triangle are in the ratio 1/2:1/3:1/5 and its perimeter is 155 cm, what is the difference between the largest sides?

Answer 1

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YOUR ANSWER

Let the measurements of sides of triangle be 'x'
Perimeter =155cm
sum of all sides(A+B+C) =155
$\frac{1}{2 } x + \frac{1}{3} x + \frac{1}{5} x = 155$
lcm of 2,3,5 is 30,therefore
$\frac{15x + 10x + 6x}{30} = 155$
$\frac{31x}{30} = 155$
$x = \frac{155 \times 30}{31}$
$x = 5 \times 30$
$x = 150$

A = x/2 = 150/2 = 75cm
B = x/3 = 150/3 = 50cm
C = x/5 = 150/5 = 30cm

Difference between the larger sides=
=A-B
=(75-50)cm
=25cm