Chemistry, asked by nayeemachem, 23 hours ago

The molecular formula of the compound CH2O,when the molecular weight is 96 and vapour density 24 is
C2H2O2
C3H6O3
C4H8O4
CH2O

Answers

Answered by schandrasaikrishna
0

Answer:

Emperical formula is (CH2O)x

now ,

molecular weight of original compound is 96

vapour density of compound is 24

molecular weight =2×VD

2×24=48

x = (original mwt )/ mwt

96/48=2

the formula of compound is C2H4O2

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