The molecular formula of the compound CH2O,when the molecular weight is 96 and vapour density 24 is
C2H2O2
C3H6O3
C4H8O4
CH2O
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Answer:
Emperical formula is (CH2O)x
now ,
molecular weight of original compound is 96
vapour density of compound is 24
molecular weight =2×VD
2×24=48
x = (original mwt )/ mwt
96/48=2
the formula of compound is C2H4O2
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