Question

The molecular mass of an oxide of an element is 44. the equivalent weight of elemint is 14

Answer 1

you mean, The molecular mass of an oxide of an element is 44. the equivalent weight of that element is 14. then find atomic mass of the element.

solution : Let us consider that atomic mass of element is M g/mol and valency of element is x

then, chemical formula of element oxide is $M_2O_x$

and then molecular weight of compound = (2M + 16x)

a/c to question,

molecular mass of oxide = 44 g/mol

so, (2M + 16x) = 44

or, M + 8x = 22.....(1)

again, equivalent weight of element is 14.

so, equivalent weight = atomic mass /valency

or, 14 = M/x

or, M = 14x.....(2)

from equations (1) and (2),

12x + 8x = 22 => x = 1

so, M = 14 g/mol

hence, atomic mass of element is 14g/mol and element is Nitrogen.