The molecular weight of a gas is 40 at 400 kelvin if 120 grams of this gas has a volume of 20 litres. Find the pressure of gas in ATM
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32
using the universal gas equation
PV = nRT
P(20) = 120/40 (0.0821)(400)
P = 4.926 atm
which is approximately equal to 5 atm.
here,
P is pressure of the gas
V is volume of the gas
n is moles of the gas (n = given weight/molecular weight)
R is universal gas constant
T is temperature of the gas
hope it helps u!!!
PV = nRT
P(20) = 120/40 (0.0821)(400)
P = 4.926 atm
which is approximately equal to 5 atm.
here,
P is pressure of the gas
V is volume of the gas
n is moles of the gas (n = given weight/molecular weight)
R is universal gas constant
T is temperature of the gas
hope it helps u!!!
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13
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