What is the Escape velocity?derive expression for Escape velocity from the surface of planet Earth
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Ve = √2GM/R
here , g = GM/R^2
GM = gR^2
therefore Ve = √ 2gR^2/R
=√2gR
the escape velocity of a body in the surface of the earth is about 11.2 km/s
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here , g = GM/R^2
GM = gR^2
therefore Ve = √ 2gR^2/R
=√2gR
the escape velocity of a body in the surface of the earth is about 11.2 km/s
hope this answer is useful to u if helps plz mark it as brain list
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