Question

The molecular weight of O, and SO2 are 32 and
64 respectively. At 15°C and 150 mmHg
pressure, one litre of O, contains N' molecules.
The number of molecules in two litres of SO,
under the same conditions of temperature and
pressure will be

Answer 1

SoluTion :-

$\sf {Given :-}\\\\\\\sf{T = 15^o C}\\\\\sf{P = 759\ mm}\\\\\\\sf{Volume\ of\ O_2 = V_1 = 1\ Lit}\\\\\sf{No.\ of\ molecules\ of\ O_2=n_1 = N}\\\\\sf {Volume\ of\ SO_2 =V_2 = 2\ Lit}\\\\\sf {No.\ of\ molecules\ of\ SO_2=n_2 =?}\\\\\\\\\sf {Formula : \boxed {\frac{V_1}{N_1} = \frac{V_2}{N_2}} ....Avogadro's\ law}\\\\\\\\\sf {\frac{1}{N}=\frac{2n}{2} }\\\\\\\sf {Hence,\ n_2 = 2N}\\\\\\\sf {Answer= (c)\ 2N}$

Answer 2

If 1 L of one gas contains N molecules, 2L of any gas under the same conditions will contain 2 N molecule

I hope this helps ( ╹▽╹ )