Question

The moment of a force of 5 N about a point P is 2 N m. Calculate the distance of point of application of the force from the point P.​

Answer 1

Answer:

Given : F=5 N

Moment of force (or torque ) τ=20 Nm

Let the distance of point of application of force from point P be d.

∴ τ=Fd

OR 20=5×d ⟹d=4 m

Answer 2

Answer:

Given : F = 5N

moment of force (or torque) = 20 Nm

Let the distance of point of application of force from point P be d

torque = F.d

20= 5 x d

d = 4m