Question

the moment of force about a fixed end P of a rod PQ of length 2 metre is 30 Nm. what is the force applied at the free point Q of the rod?​

Answer 1

Solution-

$\sf\large{\red{Given,}}$

• M = 30 N m
• d = 2 m

$\sf\large{\red{We\:know\: that,}}$

Force (F) $=\sf\dfrac{Moment\:of\:force(M)}{Distance(D)}$

$\sf\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\dfrac{30}{2} = 15 N$

So, a force of 15 N must be applied to the rod.

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