Physics, asked by navi123, 1 year ago

the moment of inertia of a hollow thick spherical shell of mass M and its inner radius R1 and outer radius R2about its diameter is

Answers

Answered by YadavShashi
1
Rho = M/ 4/3π(R2 cbe - R1 cubr)

I shell = 2/5M2R2square -2/5M1R1square

M2 = rho * 4/3πR2 cube
M1 = MR1CUBE/R2CUBE -R1CUBE

PUTTING VALUES

I = 2M(R2^5 -R1^5) / 5(R2 cube -R1cube)
Answered by HALFBLOODPRINCE123
0
Rho = M/ 4/3π(R2 cbe - R1 cubr)

I shell = 2/5M2R2square -2/5M1R1square

M2 = rho * 4/3πR2 cube
M1 = MR1CUBE/R2CUBE -R1CUBE

PUTTING VALUES

I = 2M(R2^5 -R1^5) / 5(R2 cube -R1cube)
Similar questions