Question

The moment of inertia of a particle about an axis of rotation is 0.2kg m2 if the angle of momemtum of the particle about the axis
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Answer 1

w f =w+αt→0=60+α×300α= 5−1

now to calculater w after 2 min

w 2 =60− 51 120=36

L=Iw=2×36=72Kgm

2 /s

Answer 2

Answer:

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