Question

The moment of inertia of a solid sphere about a tangent whose mass is 10 kg and radius is 10 cm is

Answer 1

Answer:

$\large\bold\red{0.14\:Kg\:{m}^{2}}$

Explanation:

We know that,

Moment Of Inertia , I of a solid sphere about a tangent is given by,

$\huge\bold{I = \frac{7}{5} M {R}^{2} }$

where,

M = Mass of the solid sphere

R = Radius of the solid sphere

Now,

In the above situation,

It is being given that,

M = 10 Kg

R = 10 cm = 0.1 m

Therefore,

pUtting tge values of respective terms,

we get,

$= > I = \frac{7}{5} \times 10 \times {(0.1)}^{2} \\ \\ = > I = 14 \times {10}^{ - 2} \\ \\ = > I = 0.14$

Hence,

Moment Of Inertia, I =$\large\bold{0.14\:Kg\:{m}^{2}}$