Question

The moment of inertia of a thin rod of mass M and length L about an axis passing through its centre and normal to its length is given by ML2/12. Using theorem of parallel axes, find its moment of inertia about an axis passing through on end and normal to its length, if L = 1m and M = 0.2 Kg.

Answer 1

moment of inertia about an axis passing through on end and normal to its length=ML²/12 + ML²/4=ML²/3
so L=1m & M=0.2Kg.... putting these values in ML²/3 we get 1/15