Question

the moment of inertia of a thin rod of mass M and length L about an axis passing through its center and normal to its length is given by ml^2/12. using theorem of parallel axes, find its mkment of inertia about an axis passing througth on end and mormal to its length , if L = 1m and M = 0.2kg

Answer 1

I about centre of mass = ml2/12 = IoI about one of its ends = ml2/12 + ml2/4 ( by perpendicular axis theorem)= ml2/3 = 4Io