the moment of inertia of a uniform circular disc about a tangent given by 5/4MR^2 find moment of inertia
Answers
Answered by
0
it will be 1/2 MR^2
Nextly in case of disc go w.r.t to area
saha1234:
firstly draw the diagram
then let area of disc to be A
now calculate mass/ area = M /A
now for small dx element its area will be circumference * width
A = 2 pie x * dx
for mass of dx element M * 2 pie x *dx /A
substitute A as pie R^2
now dI dx = 2M /R^2 [x * dx * x^2 ]
now last step just to integrate this dI dx = 2M / R ^2 integrate from 0 to R ( x ^3.dx )
and at last answer will be 1/2 MR^2
Similar questions