The moment of inertia of a uniform circular disc of radius R and mass M about an Axis touching the disc at its diameter and normal to the disc is ????
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Consider the situation shown in the below figure.

As we know the moment of inertia of the circular disc of mass m and radius R about its own axis passing from the centre and perpendicular to the plane is.
Icm=12mR2
So, the moment of inertia of the disc about the axis passing through its edge and perpendicular to its plane can be calculated by using parallel axis theorem.
I=Icm+md2=12mR2+mR2⇒I=32mR2
Hope this information will clear your doubts about the topic.

As we know the moment of inertia of the circular disc of mass m and radius R about its own axis passing from the centre and perpendicular to the plane is.
Icm=12mR2
So, the moment of inertia of the disc about the axis passing through its edge and perpendicular to its plane can be calculated by using parallel axis theorem.
I=Icm+md2=12mR2+mR2⇒I=32mR2
Hope this information will clear your doubts about the topic.
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