The moment of inertia of a uniform semicircular wire of mass M and radius r about a line perpendicular to the plane of the wire through the center is
(a) Mr²
(b) ½Mr²
(c) ¼Mr²
(d) (2/5)Mr².
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answer is (a)Mr raised to the power 2
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Answer ⇒ Option (a) .
The moment of inertia of a uniform semicircular wire of mass M and radius r about a line perpendicular to the plane of the wire through the center is ''Mr²''.
Explanation ⇒ According to the question, the mass of the wire is at a distance r away from the axis.
We know that the moment of the Inertia in such case will be given by the formula,
Moment of Inertia = Mv²
where, m is the mass and r is the Perpendicular distance.
Hence option (a). is correct.
Hope it helps.
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