Physics, asked by PhysicsHelper, 1 year ago

The moment of inertia of a uniform semicircular wire of mass M and radius r about a line perpendicular to the plane of the wire through the center is

(a) Mr²
(b) ½Mr²
(c) ¼Mr²
(d) (2/5)Mr².

Answers

Answered by kanishka2002
12
answer is (a)Mr raised to the power 2
Answered by tiwaavi
42

Answer ⇒ Option (a) .

The moment of inertia of a uniform semicircular wire of mass M and radius r about a line perpendicular to the plane of the wire through the center is ''Mr²''.



Explanation ⇒ According to the question, the mass of the wire is at a distance r away from the axis.

We know that the moment of the Inertia in such case will be given by the formula,

Moment of Inertia = Mv²

where, m is the mass and r is the Perpendicular distance.


Hence option (a). is correct.



Hope it helps.

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