Question

The moment of inertia of a wheel about the axis of rotation is 3.1 MKS units its kinetic energy will be 600 jewel of the of a period of rotation is

Answer 1

period of rotation of the wheel is π/10 sec

moment of inertia of wheel about the axis of rotation is I = 3.1 kgm² [ MKS unit of moment of inertia is kgm² ]

rotational kinetic energy = 600J

rotational kinetic energy of wheel = 1/2 Iω² , where ω is angular frequency.

so, 600J = 1/2 × 3.1 × ω²

⇒ω² ≈ 400 = (20)²

⇒ω = 20 rad/s

period of rotation = 2π/angular frequency = 2π/ω

= 2π/20 = π/10 sec

hence, period of rotation of the wheel is π/10 sec

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Answer 2

$\huge\bold\purple{Answer:-}$

moment of inertia of wheel about the axis of rotation is I = 3.1 kgm² [ MKS unit of moment of inertia is kgm² ]

rotational kinetic energy = 600J

rotational kinetic energy of wheel = 1/2 Iω² , where ω is angular frequency.

so, 600J = 1/2 × 3.1 × ω²

⇒ω² ≈ 400 = (20)²

⇒ω = 20 rad/s

period of rotation = 2π/angular frequency = 2π/ω

= 2π/20 = π/10 sec

hence, period of rotation of the wheel is π/10 sec