the moment of inertia of an uniform cIrcular disc about its central axis is "i" its M.I about a tangent in its plane is equal to
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moment of inertia of disc at tangent=5/4mr²=I +mr² (by parallel axis theorem)
I=5/4mr²-mr²=1/4mr²
by perpendicular axis theorem
I+I=I°(perpendicular to plane)
1/4mr²+1/4mr²=mr²/2
I=5/4mr²-mr²=1/4mr²
by perpendicular axis theorem
I+I=I°(perpendicular to plane)
1/4mr²+1/4mr²=mr²/2
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