Question

The moment of inertia of nacl molecule with bond length r about an axis perpendicular to the bond and passing through the centre of mass is

Answer 1

# Answer- I=[(mNa.mCl)/(mNa+mCl)]r^2

# Explanation-

# Moment of inertia-

Moment of inertia is the inertia of a rotating body with respect to its rotation.

For any diatomic molecule

Moment of inertia arpund centre of mass is given by

I=[(m1.m2)/(m1+m2)]r^2

Consider NaCl molecule with atomic mass of sodium mNa and that of chlorine mCl with bond length r.

Moment of inertia through centre of mass is given by

I=[(mNa.mCl)/(mNa+mCl)]r^2