Question

the momentum of a body in two perpendicular direction at any time T are given by PX equal to 3t square + 6 and b y equal to 3t square by 2 + 3 the force acting on a body it equal to 2 second is

Answer 1

Force is rate of change of momentum
Force along x = d(momentum along x)/dt
hence
Force along x=derivative of (2t^2+6)
=4t
=4*2
=8
For force along y axis
do the same you will get
Force along y =6
F resultant =
$\sqrt{fx {}^{2} + fy {}^{2} }$
=
$\sqrt{6 {}^{2} + 8 {}^{2} }$
=10
Hope it helps
Tap the blue crown