Question

the momentum of a body in two perpendicular directions at any time T are given by PX equal to 2t^ + 6 and p y equal to 3t^/ 2 + 3 the force acting on the body at equal to 2 seconds

Answer 1

Force is rate of change of momentum
Force along x = d(momentum along x)/dt
hence
Force along x=derivative of (2t^2+6)
=4t
=4*2
=8
For force along y axis
do the same you will get
Force along y =6
F resultant =
$\sqrt{fx {}^{2} + fy {}^{2} }$
=
$\sqrt{6 {}^{2} + 8 {}^{2} }$
=10
Hope it helps
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Answer 2

Answer:

Force along x = d(momentum along x)/dt

hence

Force along x=derivative of (2t^2+6)

=4t

=4*2

=8

For force along y axis

do the same you will get

Force along y =6

F resultant =

\sqrt{fx {}^{2} + fy {}^{2} }

fx

2

+fy

2

=

\sqrt{6 {}^{2} + 8 {}^{2} }

6

2

+8

2

=10