Question

the momentum of a body is increased by 50% . what is the % change in kinetic energy​

Answer 1

$\huge\mathfrak\red {Answer}$

the new kinetic energy (k') = (p')² / 2m . therefore the percentage change is , (k' - k ) / k x 100 = ( 2.25 k - k ) / k x 100 = 125 % .