Question

the momentum of a body of mass 15 kg is 50 kg m/s find its kinetic energy.


pls answer pls !!
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Answer 1

Explanation:

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${\bigstar\huge{\boxed{\tt {\color{red}{Question}}}}}\bigstar$

:$\Longrightarrow$ ● The momentum of a body of mass 15 kg is 50 kg m/s find its kinetic energy.

${\bigstar\huge{\boxed{\tt {\color{red}{To\ find}}}}}\bigstar$

:$\Longrightarrow$ ● We have to find the kinetic energy of the given body.

${\bigstar\huge{\boxed{\tt {\color{red}{Given}}}}}\bigstar$

:$\Longrightarrow$ ● The momentum of a body of mass 15 kg is 50 kgm/s.

${\bigstar\huge{\boxed{\tt {\color{red}{Solution}}}}}\bigstar$

:$\Longrightarrow$ ● The relation between the momentum and kinetic energy is:-

:$\Longrightarrow$ $\mathsf\pink{K.E\ =\ \dfrac{P²}{2m}}$

:$\Longrightarrow$ And here:-

:$\Longrightarrow$ ● "P" is for momentum.

:$\Longrightarrow$ ● "K.E" is for kinetic energy.

:$\Longrightarrow$ ● "m" is for mass.

$\bf{\bigstar}$$\text{\large\underline{\bf{By\ substituting\ the\ values:-}}}$

:$\Longrightarrow$ $\mathsf\blue{K.E\ =\ \dfrac{(50kgms^‐¹)²}{2(15kg)}}$

:$\Longrightarrow$ $\mathsf\blue{K.E\ =\ \dfrac{50kgms^‐¹ × 50kgms^‐¹}{30kg}}$

:$\Longrightarrow$ $\mathsf\blue{K.E\ =\ \dfrac{50 × 50kg²m²s^‐²}{30kg}}$

:$\Longrightarrow$ $\mathsf\blue{K.E\ =\ \dfrac{2500kg²m²s^‐²}{30kg}}$

:$\Longrightarrow$ $\mathsf\blue{K.E\ =\ \dfrac{2500kgm²s^‐²}{30}}$

:$\Longrightarrow$ $\mathsf\blue{K.E\ =\ 83.33kgm²s^‐²}$

:$\Longrightarrow$ $\fbox\blue{K.E\ =\ 83.33J}$

$\fbox\purple{Hence,\ the\ kinetic\ energy\ of\ the\ body\ is\ 83.33J}$

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Answer 2

Given:-

⎔Momentum of a body is 50 kg m/s.

Mass of a body is 15 kg.

⠀

To find:-

◆ It's kinetic energy.

⠀

Solution:-

$\longmapsto \sf \: KE = \dfrac{(50 \: kgm {s}^{ - 1} )^2}{2(15 \: kg)}$

⠀

$\longmapsto \sf \:KE = \dfrac{50 \: kgm {s}^{ - 1} \times 50 \: kgm {s}^{ - 1} }{30 \: kg}$

⠀

$\longmapsto \sf \: KE = \dfrac{50 \times 50 \: {kg}^{2} {m}^{2} {s}^{ - 2} }{30 \: kg}$

⠀

$\longmapsto \sf \:KE = \dfrac{2500 \: {kg}^{2} {m}^{2} {s}^{ - 2} }{30 \: kg}$

⠀

$\longmapsto \sf \:KE = \dfrac{2500 \: kg {m}^{2} {s}^{ - 2} }{30}$

⠀

$\longmapsto \sf \:KE = 83.33 \: kg {m}^{2} {s}^{ - 2}$

⠀

$\longmapsto{\underline{\boxed{\purple{\sf{KE = 83.33 \: J}}}}}$

⠀

Hence,

the kinetic energy is 83.33 Joule.