Question

the momentum of body increased by 25% then kinetic energy is increased by about​

Answer 1

Explanation:

The relation between kinetic energy, K and momentum p is the following.

K=p^2/2m…………(1)

Since, body is the same, mass remains constant.

If momentum increases by 25%, then new momentum will be

p’=1.25 p. Hence, new kinetic energy will be K’=(1.25)^2p^2/2m……….(2)

Then, (K’-K)/K=[p^2/2m(1.25)^2–1)]/(p^2/2m)=[(1.25)^2–1]=1.56–1.=0.56

Therefore % increase in kinetic energy=0.56x100=56%.

Answer 2

Answer:

56.25%

Explanation :

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