Math, asked by mohitosh14, 9 months ago

Factories :
  {x}^{4}  - (x - y) ^{4}
 {a}^{4}  - 2a {}^{2} b {}^{2}  + b {}^{4}

Answers

Answered by Anonymous
11

Answer:

Main Aim:

  • To factories x⁴-(x-y)⁴ and a⁴-2a²b²+b⁴.

Let us factories the first one.

a) x⁴-(x-y)⁴ (This is in form of identity (a²-b²))

= (x²)²-[(x-y)²]² (Exponents are in form of Multiplication)

= [x+(x-y)[x-(x-y)]

(As we know, (a-b)² = (a+b)(a-b); Thus, this is the factorised form where x is a and (x-y) is b)

or,

\tt\blue{\boxed{[x+(x-y)] \ [x-(x-y)]}}

Let us factories the second one.

b) a⁴-2a²b²+b⁴ (In the form of identity -2ab+)

= (a²)²+(b²)²-2(a²b²) {Now, divided the exponents}

= (a²-b²)² {Now, inform of (a-b)²}

= (a²-b²) (a²-b²) {Factorised form; As we know (a-b)² = -2ab+, hence, this will be the answer}

or,

\tt\blue{\boxed{({a}^{2}-{b}^{2}) \ ({a}^{2}-{b}^{2})}}


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Answered by Anonymous
1

Answer:

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