Question

The momentum of inertia of a thin rod mass M and length L about an एक्सिस passing through its centre and normal to its length is given by MLsquare/12 using theorem of parallel एक्सिस find its momentum of inertia about an एक्सिस passing through on end and normal to its length if L=1m and M=0.2

Answer 1

By using parallel axis theorem, moment of inertia of rod passing through one end and normal to its length = I
I = ML²/12 + ML²/4 = ML²/3
I = 0.2 × 1² / 3
I = 0.067 kgm²