Math, asked by sudharshangopinath, 11 months ago

the monthly income of a and b are in the ratio 8 7 and their expenditures are in the ratio of 19 is to 16.if each save rupees 2500 per month what will be the income of each

Answers

Answered by Anonymous
7

Answer:

Let monthly income of A and B be 8x and 7x

Let monthly expenditure of A and B be 19y and 16y respectively.

Savings of A = 8x - 19y = 5000

Savings of B = 7x - 16y = 5000

Solving for x and y

x = 3000

y = 1000

Thus,

Monthly income of A = 8x = 8 x 3000 = ₹ 24000

Monthly income of B = 7x = 7 x 3000 = ₹ 21000

Answered by ItzRadhika
4

SOLUTION:-

Let the monthly income of A and B be Rs.8x and Rs. 7x Respectively,

and let their expenditure be Rs. 19y and Rs . 16y Respectively.

Then

A's monthly savings = Rs.(8x-19y)

And

B's monthly savings = Rs. (7x-16y)

But, the monthly savings of each is Rs. 5000

8x-19y=5000............(1)

7x-16y=5000............(2)

Multiply eq 2 by 19 eq1 by 16 and subtracting the results

we get,

(19×7-16×8)x= (19×5000-16×5000)

=( 133-128)x = 5000×(19-16)

= 5x=15000

x= 3000

A's monthly income = Rs.8x= Rs.(8×3000)=Rs. 24000.

B's monthly income = Rs. 7x = Rs. (7×3000)= Rs . 21000.

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