Question

The monthly S.I on Rs.10,000 at the rate of 18% is

Answer 1

Given:-

•Principal = 10,000 rupees

• Rate = 18%

• Time = $\dfrac{1}{12}$ years

To Find:-

•Simple Interest = ?

Solution:-

Here,

• P = 10000 rupees
• R = 18%
• T = $\dfrac{1}{12}$ years

As we know,

$\: \: \sf \: simple \: interest = \frac{principal \times rate \times time}{100}$

Now substitute the values

$\: \: \sf \: simple \: interest = \frac{10000 \times 18 \times \frac{1}{12} }{100 } \\ \\ \: \: \sf \: simple \: interest = 150 \: rupees$

Hence,simple interest is 150 rupees.

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Answer 2

_________________________

$\: \\ \:$

Given :—

$\:$

• Principle = Rs. 10,000
• Rate = 18%
• Time = 1/12 yrs

$\:$

To Find :—

$\:$

• Simple interest

$\:$

Solution :—

$\:$

Formula used :—

$\:$

$\begin{gathered}{ \boxed{ \underline{ \bf{ \blue{SI \frac{ = P \times R \times T }{100} }}}}} \end{gathered}$

SI = 10000×18×(1/2)/100

$\:$

$\longrightarrow \sf{SI = Rs.150}$

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