Question

The monthly salary of a person was Rs 320 for each of the first three years. He next got annual increments of Rs 40/month for each of the following successive 12 years. His salary remained stationery till retirement when he found that his average monthly salary during his service period was Rs.698. Find the period of his service

Answer 1

Answer:

total salary for first 3years=3*12*320=11520

rs 40 per month increment for each of following 12 consecutive years.

for 4th year monthly salary=rs 360

for 5th year monthly salary= rs 400

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.

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for 15th year monthly salary = 360+(12-1)40= rs 800

his total salary for these 12 years = 12*12/2*(360*2+(12-1)*40)

= rs 83520

His monthly salary till retirement = rs 800

let,no.of years he worked with this salary = x

his average salary = (11520+83520+(800*12*x))/((3+12+x)*12)

= 694(given)

by solving this x= 23.49

total service period = 23.49+12+3 =38.49>25

so answer is a

Answer 2

Answer:

ok I try to answer your question