Math, asked by Darerer, 7 days ago

The monthly SI on Rs. 1000 is Rs. 15,then find the annual rate.

Answers

Answered by Anonymous
227

Given:

  • Principal = 1000 rupees
  • Simple Interest = 15 rupees
  • Time = 1 year

To Find:

  • Rate = ?

Solution:

Given,

  • P = 1000 rupees
  • S.I = 15 rupees
  • T = 1 year

Monthly interest = 15 rupees

Yearly interest = 15 × 12 = 180 rupees

As we know that

 \:  \:  \:  \:  \sf \implies \: rate =  \frac{simple \: interest \times 100}{principal \times 100}

Now put the values

 \:  \sf \implies \: rate =  \frac{180 \times 100}{1000 }  \\  \\  \:  \sf \implies \: rate =  18 \: percent

Therefore, rate of interest per annum is 18%.

\:\:\:\:\:___________________

More to know:

  • Simple Interest = PRT/100
  • Time = Simple Interest × 100/Principal × Rate
  • Principal = Simple Interest × 100/Rate × Time

Answered by ranjanasingh25812
2

Answer:

18 years

Step-by-step explanation:

P-1000

T-1 year

SI-per month 15,then per year 15×12=180

So , rate of interest = SI×100÷P×T

180×100÷1000×1=18000÷1000=18%

Rate of the interest is 18%

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