Math, asked by rohandeshmukh, 11 months ago

The most common oxidation state of lanthanoids is

a) 4+
b) 3+
c) 6+
d) 2+

Answers

Answered by chinmayi3
3

B. 3+

Step-by-step explanation:

Removal of outermost 2 electrons of 6s and 1 electron from 4f

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